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QUESTION

# How do I find the number of grams in 1 mole of sulfuric acid. Then calculate the number of grams of sulfuric acid needed to make a 1-L solution of sulfuric acid in water that has a molarity of 3?

You will need "294.24 g H"_2"SO"_4" to make 1 liter of a 3 M solution.

You need to first determine the molar mass of sulfuric acid, which is the number of grams in 1 mole of sulfuric acid. We use the atomic weights on for each element in sulfuric acid, writing the atomic weight in grams per mole.

The formula for sulfuric acid is "H"_2"SO"_4". To find the molar mass, multiply the subscript for each element times its atomic weight in g/mol. Then add the results.

H: 2 x 1.008 g/mol = 2.016 g/mol S: 1 x 32.06 g/mol = 32.06 g/mol O: 4 x 15.999 g/mol = 63.996 g/mol Molar mass of "H"_2"SO"_4" = 98.08 g/mol

Note: You can also find the molar mass by doing an online search.

is the number of moles of a substance per liter of solution. A 3 M solution of sulfuric acid contains 3 moles of sulfuric acid per liter of solution. Determine the mass of sulfuric acid required to make a 3 M solution.

3 cancel("mol") "H"_2"SO"_4" x "98.08 g"/cancel("1 mol") = "294.24 g H"_2"SO"_4"