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# How do I find the value of sin 45+cos 60?

##(1+sqrt(2))/2##

assuming the values are in degrees, ##sin(45)=sin(pi/4)=sqrt(2)/2## ##cos(60)=cos(pi/3)=1/2## so ##sin(45)+cos(60)=sqrt(2)/2 + 1/2## ##=(1+sqrt(2))/2##