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QUESTION

How do I find the x-intercepts of the graph of y=x^2-11x+18?

To find the x-intercepts of the graph of y=x^2-11x+18 substitute 0 for y and solve for x.

0=x^2-11x+18

Now, factor the quadratic expression on the right.

0=(x-2)(x-9)

and set each factor equal to 0 and solve.

(x-2)=0 or (x-9)=0 =>x=2 or x=9

The x-intercepts of any function y = f(x) are found

by setting f(x)=0 since the y-coordinate of any point on the

x-axis is zero.

See image below.