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How do i solve that problem
If logx 3=a, logx 5= b and logx 2=c
Find the expression that equals :
A)logx 15/2
B)logx 6x^2
C)logx 300
D)logx (40+20)^1/2
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** **** 15/2 = **** ((5 * ** * ** * **** * * **** * - **** * = b * a - c B)
logx **** * **** * * logx **** logx ** X ** * 2 logx * = **** * * **** * + 2 * * = * * * + 2 ** ****
300 * **** ( 3 * *** * ***** * * logx *** * * * **** 10^2 = * + 2 **** ** * * * * **** * 5 X * * * * * 2 ***** * * **** *** * *
* 2 **** * + * **** * * * * ** + *** ** ****
*************** logx 60 * *** * logx (2^2 * 3 * 5 * * * *** (logx *** + logx * * logx * * **** ****** * + * + *** * ****
* * ******* * * * ******* = (a+b)/2 * *