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QUESTION

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A car is moving at 10m/s when it begins to be accelerated at 2.5m/s^2. (A) how long does the car take to reach a speed of 25 m/s? (B) how far does it go during this period?

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** **** *** ********* ********* equation: ** * *** where u is *** ******* ********* ** *** final ********* * is *** ************ and * ** *** time ***** *** *** vehicle to ***** a ***** ******** ** * from ** ******* velocity ** u ** ** * *** ******* ** * ** ** * ** + 25t ** *** = ***** = 15 or * = ** / 25 * * ** * * * seconds ** ** ***** * ******* for *** *** ** ***** * ***** of ** ***** **** **** the following ******* :- * = ** + **** ) * * X ** *** * * ut * at^2 /2 ------- Eq **** ******** all ***** of ** ** **** *** * (u +at * ^ **** *** = *** ******** + ***** * *** * ******* /2 * ** ) or **** *** * 2a(ut ***** *** ------Eq * **** ** ****** ** ***** * ** * **** ** ************ ****** ** ** * ** Eq * ** have *** **** * 2a(ut ***** *** * *** * ****** ** **** *** ******* :- *** * u^2 ** * * X s ***** * is *** ******** travelled ** *** *********** = **** +2 * 25 * *** s * ***** - 10^2) * ** * **** - **** ** * ****** * 210 or * * 210 mHence *** car travels 210 metres ****** **** ****** * ** * seconds *

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Robert
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*** using equation ** ************* speed ******* ********** * **** * (25-10)/25t=6 s *** ***** * seconds ** ***** ******** using v^2 * *** *********************** * ********************* **** it goes ** *** ** *********** s=ut+(at^2)/2S=10×6 * ************** * 45= 105 *

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**** *** answer well *********

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************* * ** final ******** ******* ** ******* velocity=10m/sa ** acceleration ******* ** **** takenSubstitute **** *** ******** ** get ***************************************** ***** ************** *** does it ** ****** this **** (S)S=So+Ut +1/2at²S=final ********** ** ******* ************ ** ******* *************** is ********************** time ******************** into equation ** *************************************** ******** covered is *** ***

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