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QUESTION
How do you calculate ##Arccos (sin (pi/6))##?
Find ##arccos(sin (pi/6))##
Ans: ##+- pi/3##
##sin (pi/6) = 1/2## therefor ##arccos (sin(pi/6)) = arccos (1/2)## On the trig unit circle,
##cos x = 1/2## --> arc ##x = +- pi/3##
