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# How do you calculate the percent yield of copper?

You divide the actual yield by the theoretical yield and multiply by 100.

**EXAMPLE**

What is the if 0.650 g of copper are formed when excess aluminum reacts with a 2.00 g of copper(II) chloride dihydrate according to the equation

**Step 1.** Write the balanced chemical equation

3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 2H₂O

**Step 2.** Calculate the theoretical yield of Cu

**(a)** Calculate the moles of 3CuCl₂·2H₂O

##"2.00 g CuCl"_2·2"H"_2"O" × ("1 mol CuCl"_2·2"H"_2"O")/("170.5 g CuCl"_2·2"H"_2"O") = "0.011 73 mol CuCl"_2·2"H"_2"O"##

**(b)** Calculate the moles of Cu

##"0.011 73 mol CuCl"_2·2"H"_2"O" × "3 mol Cu"/("3 mol CuCl"_2·2"H"_2"O") = "0.011 73 mol Cu"##

**(c)** Calculate the theoretical yield

##"0.011 73 mol Cu"× "63.55 g Cu"/"1 mol Cu" = "0.7455 g Cu"##

**Step 3.** Calculate the percent yield.

% yield = ##"theoretical yield"/"actual yield" × 100 % = "0.650 g"/"0.7455 g" × 100 %## = 87.2 %