How do you convert 0.83 (3 repeating) to a fraction?

##" so "x= 0.8bar3 = 5/6##

To format this question type you write: 0.8bar3

But you use the hash key just before 0.8bar3 and also at the end. So you end up with

##" "0.8bar3##

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let ##x=0.8bar3##

Then ##10x = 8.bar3##

So ##(10x-x)=" " 8.3333bar3## ##" "underline(0.8333bar3-## Subtracting ##" "7.5##

##" "9x = 7.5##

Multiply both sides by 10

##" "90x=75##

Divide both sides by 90

##" "x=75/90 = 5/6##

##" so "x= 0.8bar3 = 5/6##