Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
QUESTION
How do you evaluate ##arcsin(sqrt 3/2)##?
##arcsin(sqrt(3)/2)=60°=pi/3##
##sqrt(3)/2## is a known value, and the main angle ##alpha## that has ##sin(alpha)=sqrt(3)/2## is ##alpha=60°=pi/3##. Because arcsin is a function ##RR->[-1;1]##, we take only the value ##alpha=pi/3##, without the periodic values. So ##arcsin(sqrt(3)/2)=60°=pi/3##.
