Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
How do you factor ##x^3y^3 - 8##?
##=(xy-2)(x^2y^2+2xy+2)##
##x^3y^3-8## or ##(xy)^3-2^3## Since ##a^3-b^3=(a-b)(a^2+ab+b^2)## or ##=(xy-2)((xy)^2+2xy+2)## ##=(xy-2)(x^2y^2+2xy+2)##