How do you find the 6 trig functions of 120 degrees?

##sin120=sqrt(3)/2##

##cos120=-1/2##

##tan120=-sqrt(3)##

##ctg120=-sqrt(3)/3##

##sec120=-2##

##csec120=(2sqrt(3))/3##

To calculate ##sin120## and ##cos120## you can use the reduction formula, which says, that

##sin(180-x)=sinx## and ##cos(180-x)=-cosx##

Rest of the functions can be calculated as:

##tanx=sinx/cosx##

##ctgx=1/tanx##

##secx=1/cosx##

##csecx=1/sinx##