How do you find the 6 trigonometric functions for 150 degrees?

Refer to explanation

We have that

##sin(150)=sin(180-30)=sin30=1/2##

##csc(150)=1/sin(150)=2##

##cos (150) = –cos(30) =-sqrt3/2 ##

##sec(150) = 1/cos(150)=-2/sqrt3##

##tan(150)=-tan(30)=-sqrt3/3##

##cot(150)=1/tan(150)=-sqrt3##