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How do you find the exact value of Sin 45degrees + cos 60degrees?
##sqrt2/2+1/2##
Recall the unit circle:
From the unit circle we can see that at ##45^o## the position of the angle on the unit circle is at ##(sqrt2/2,sqrt2/2)##
##(sqrt2/2,sqrt2/2)=(costheta,sintheta)##
So, for ##45^o##, ##sin(45^o)=sqrt2/2##
Now, from the unit circle we can see that at ##60^o## the position of the angle on the unit circle is at ##(1/2,sqrt3/2)##
##(1/2,sqrt3/2)=(costheta,sintheta)##
So, for ##60^o##, ##cos(60^o)=1/2##
So,
##sin(45^o)+cos(60^o)=sqrt2/2+1/2##