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QUESTION
How do you find the integral of ##int sec^2(5x)dx##?
##1/5 tan 5x +C##
Let 5x = u , so that ##dx= 1/5 du##
##int sec^2 5x dx = 1/5intsec^2 u du##
=##1/5 tanu +C##
= ##1/5 tan 5x +C##
