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QUESTION
How do you find the integral of ##xe^(x/2)dx ##?
By part
##u = x## ##du = 1##
##dv = e^(1/2x)##
##v = 2e^(1/2x)##
##=>2([xe^(1/2x)]-inte^(1/2x)dx)+C##
##=>2([xe^(1/2x)]-2[e^(1/2x)])+C##
##=>2e^(1/2x)(x-2)+C##
