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QUESTION

How do you find the integral of ##xe^(x/2)dx ##?

By part

##u = x## ##du = 1##

##dv = e^(1/2x)##

##v = 2e^(1/2x)##

##=>2([xe^(1/2x)]-inte^(1/2x)dx)+C##

##=>2([xe^(1/2x)]-2[e^(1/2x)])+C##

##=>2e^(1/2x)(x-2)+C##

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