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QUESTION

# How do you find the range and interquartile range for 37, 19, 13, 11, 10?

Range is 27 and interquartile range is 17 1/2.

Let us first arrange them in increasing order and data appears as

10,11,13,19,37

As the range is difference between maximum and nimimum

Range is 37-10=27

Median is the value of ((n+1)/2)^(th) term i.e. (5+1)/2=3^(rd) term i.e. 13

First quartile Q_1 is ((n+1)/4)^(th)=(1 1/2)^(th) term and third quartile Q_3 is 3((n+1)/4)^(th)=(4 1/2)^(th) term.

Hence, we can take Q_1 as (10+11)/2=10 1/2 and Q_3 as (19+37)/2=28.

As interquartile range is Q_3-Q_1, it is 28-10 1/2=17 1/2