Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
How do you find the six trigonometric functions of 300 degrees?
Use the trig unit circle as proof.
##sin 300 = sin (-60 + 360) = sin (-60) = -sin 60 =#### (-sqrt3)/2##
##cos 300 = cos (-60 + 300) = cos 60 = 1/2##
##tan 300 = (-sqrt3)/2 : (1/2) = -sqrt3##
##cot 300 = 1/(sqrt3) = (-sqrt3)/3##
##sec 300 = 1/cos 300 = -2/(sqrt3) = (-2sqrt3)/3##
##csc 300 = 1/sin 300 = 2##