How do you find x and y intercepts of ## -6x + 3y = -9##?

x-intercept is ##x = 3/2## or (3/2, 0).

y-intercept is ##y = -3## or (0, -3)

To find the x-intercept, set ##y## equal to ##0## and solve for ##x##:

##-6x + 3*0 = -9##

##-6x + 0 = -9##

##-6x = -9##

##(-6x)/-6 = (-9)/-6##

##(cancel(-6)x)/cancel(-6) = 3/3 * (-3)/-2##

##x = 1 * 3/2##

##x = 3/2## or (3/2, 0).

To find the y-intercept, set ##x## equal to ##0## and solve for ##y##:

##-6*0 + 3y = -9##

##0 + 3y = -9##

##3y = -9##

##(3y)/3 = (-9)/3##

##(cancel(3)y)/cancel(3) = -3##

##y = -3## or (0, -3)