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How do you prove ##1/(sinxcosx) - cosx/sinx = tanx##?
##1/(sinxcosx)-cosx/sinx=tanx##
##1/(sinxcosx)-cosx/sinx(cosx/cosx)=tanx##
##1/(sinxcosx)-cos^2x/(sinxcosx)=tanx##
##(1-cos^2x)/(sinxcosx)=tanx##
##sin^2x/(sinxcosx)=tanx##
##sinx/cosx=tanx##
##tanx=tanx##