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How do you simplify each expression using positive exponents ##(x^-2y^-4x^3)^-2 ##?
##y^8/x^2##
We can use exponent rules to simplify this expression. Taking a look at the original function;
##(x^-2y^-4x^3)^-2##
We can see that there are two ##x## terms inside of the parenthesis. Lets combine those first. If we multiply two terms with exponents, the exponents add, in other words;
##x^a xx x^b = x^(a+b)##
Applying this to our case, we get;
##(x^((3-2))y^-4)^-2##
##(x^1y^-4)^-2##
Now lets take a look at the exponent outside the parenthesis. Whenever we raise an exponent term to an exponent, we multiply the exponents.
##(x^a)^b = x^((a)(b))##
In our case, raising both the ##x## term and the ##y## term to ##-2## we get;
##x^((-2)(1))y^((-2)(-4))##
##x^-2y^8##
Now we have one negative exponent and one positive exponent. We need to convert the ##x## term to a positive exponent. To do that we will invert the term.
##x^-a = 1/x^a##
So to get rid of the ##-## we will move the ##x## term to the denominator.
##y^8/x^2##