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How do you simplify the expression ##(sinx-cosx)/(sinxcosx)##?
##frac{sinx-cosx}{sinx cosx} = secx - cscx##
##frac{sinx-cosx}{sinx cosx} = frac{sinx}{sinx cosx} - frac{cosx}{sinx cosx}##
##= frac{1}{cosx} - frac{1}{sinx}##
##= secx - cscx##