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QUESTION

How do you simplify the expression ##(sinx-cosx)/(sinxcosx)##?

##frac{sinx-cosx}{sinx cosx} = secx - cscx##

##frac{sinx-cosx}{sinx cosx} = frac{sinx}{sinx cosx} - frac{cosx}{sinx cosx}##

##= frac{1}{cosx} - frac{1}{sinx}##

##= secx - cscx##

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