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QUESTION
How do you solve ## cos^2x = 3/4##?
Solve ##cos^2 x = 3/4##
Ans: ##+- pi/6## and ##+- (5pi)/6##
##cos^2 x = 3/4## --> ##cos x = +- sqrt3/2##
##a. cos x = sqrt3/2 ##--> arc ## x = +- pi/6## ##b. cos x = - sqrt3/2## --> arc ##x = +- (5pi)/6##
