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QUESTION

# How do you solve ln(x^2)=16?

I found: x=e^8=2,980.95

We can use the property of the logs that allows you to take out the exponent of the argument and place it as multiplier in front of the log to get:

2ln(x)=16

rearrange:

ln(x)=16/2=8

use the definition of log to get:

x=e^8=2,980.95