Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

# How do you solve  ln (x – 2) + ln (x + 2) = ln 5?

x=-3 or x=3

Using the property that says :

 ln(a) +ln(b) = ln(a*b) We have:

ln(x-2)+ln(x+2) = ln5

ln((x-2)*(x+2)) = ln5

Rasing exponential both sides we will have:

(x-2)*(x+2) =5

Applying polynomial property on the equation above that says:

 a^2 - b^2 = (a-b)*(a+b)

We have: (x-2)*(x+2) = x^2-4

So, x^2 - 4 = 5  x^2 - 4 -5 =0 x^2 - 9 =0 (x-3)*(x+3)=0

So, x-3=0 thus x=3

Or,

x+3=0 thus x=-3