Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

QUESTION

# How do you solve log ( x +1 ) + log 7 = log 14 - log ( 2-x ) ?

As logA+logB=logAB & logA-logB=log(A/B)

Therefore, log(x+1)+log7=log14-log(2-x) can be written as log7(x+1)=log(14/(2-x)) both sides are in the form of single term logs to the same base so now we can drop the log from both sides 7(x+1)=14/(2-x) (x+1)(2-x)=14/7 -x^2+x+2=2 x^2-x=0 x(x-1)=0 x=0 OR x=1