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# How do you solve ##log x + log 5 = 2##?

use laws of logarithm: ##log AB = log A + log B##; change to single log: then change to exponential, ##x = 20## (Answer)

##log x +log 5 = 2## ##log 5x=2## exponential form: ##5x = 10^2## (in common log, the base is 10) ##5x = 100## ##x = 20## (ans)