Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
QUESTION
How do you solve ##Sin(pi/2 - x) cot(pi/2 + x) = -sin x## from 0 to 2pi?
undefined equation.
sin (pi/2 - x) = cos x (supplementary arc) ##cot (pi/2 + x) = (cos (pi/2 + x))/(sin (pi/2 + x)) = sin x/(-cos x).## The left side of the equation simplifies to: ##(cos x)(sin x/(-cos x)) = - sin x##, Then, the equation reduces to: -sin x = - sin x The equation is undefined. It is insolvable.
