Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
How do you solve the system ## y=6x - 11## and ##-2 - 3y = -7## by substitution?
Given ##"[1] "y=6x-11## ##"[2] "-2-3y = -7##
from ##"[1]"## we can substitute ##6x-11## for ##y## in ##"[2]"## ##"[3] "-2-3(6x-11) = -7##
##"[4] " -3(6x-11) = -5##
##"[5] " 6x-11 = 5/3##
##"[6] " 6x = 38/3##
##"[7] " x = 19/9##
Note that ##"[2]"## can be solved directly for ##y## ##"[8] "-3y = -5##
##"[9] " y = 5/3##
Query: Was the second equation intended to be ##-2x-3y = -7##?