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QUESTION
How do you verify ##(sin^2x - cos^2x)/(sinx + cosx)=sinx-cosx##?
Very Carefully...
The top portion of this fraction is a difference of 2 squares, meaning
##sin^2(x)-cos^2(x)=(sin(x)+cos(x))(sin(x)-cos(x))##, so
##(sin^2(x)-cos^2(x))/(sin(x)+cos(x))=((sin(x)+cos(x))(sin(x)-cos(x)))/(sin(x)+cos(x))##
##=sin(x)-cos(x)##
