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QUESTION
How do you verify ##sinx/(1-cosx) + (1-cosx)/sinx = 2cscx##?
##sinx/(1-cosx)+(1-cosx)/sinx = 2cscx##
##sinx/(1-cosx)+(1-cosx)/sinx = [sin^2x+(1-cosx)^2]/[(1-cosx)sinx]##
## = [sin^2x+cos^2x+1-2cosx]/[(1-cosx)sinx]##
## = [1+1-2cosx]/[(1-cosx)sinx]##
## = [2-2cosx]/[(1-cosx)sinx]##
## = 2cancel[1-cosx]/[cancel(1-cosx)sinx]##
## = 2/sinx##
## = 2cscx##
