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QUESTION
How do you verify ##tanA=secA/cscA##?
see below
##tanA=secA/cscA##
Right Side:##=secA/cscA##
##=(1/cosA)/(1/sinA)##
##=1/cosA*sinA/1##
##=sinA/cosA##
##=tanA##
##:.=##Left Side
