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QUESTION

How many moles of&nbsp;O&nbsp;are in 10.8mol&nbsp;Fe(NO3)3?

There are "97.2 mol of O" in "10.8 mol of Fe"("NO"_3)_3.

There are 9 atoms of "O" in 1 of "Fe"("NO"_3)_3, so there are "9 mol of O" in "1 mol of Fe"("NO"_3)_3.

Your conversion factor is either "9 mol O"/("1 mol Fe"("NO"_3")_3) or ("1 mol Fe"("NO"_3)_3)/"9 mol O".

You choose the one that cancels units to give the desired units on the answer.

10.8 color(red)(cancel(color(black)("mol Fe"("NO"_3)_3))) × "9 mol O"/(1 color(red)(cancel(color(black)("mol Fe"("NO"_3)_3)))) = "97.2 mol O"