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QUESTION
How to prove that ##sin (pi/2 - theta)## = ##cos theta## ?
see explanation
using appropriate ##color(blue)" Addition formula " ##
##• sin(A ± B) = sinAcosB ± cosAsinB ##
hence ## sin(pi/2 -theta) = sin(pi/2) costheta - cos(pi/2)sintheta ##
now ## sin(pi/2) = 1 " and " cos(pi/2) = 0 ##
hence ## sin(pi/2)costheta - cos(pi/2)sintheta = costheta - 0 ##
##rArr sin(pi/2 - theta ) = costheta ##
