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# I can't seem to figure out why there is no input asked when an invalid number is asked for. The code I have so far is below: int main() { cout...

I can't seem to figure out why there is no input asked when an invalid number is asked for. The code I have so far is below:

int main()

{

cout << "Please enter your numbers: "; // Output to user

string st; // Initialize Variable

cin >> st;// Input numbers

stringstream stream(st); // String stream

int arr[50]; // Max array

int count = 0; // Initialize variable

int number;

while (stream >> number) // While loop

{

arr[count] = number; // Array

count++; // Increment count

if (stream.peek() == ',')

stream.ignore(); // Checks for comma and ignores them

}

for (int i = 0; i < count; i++) // For Loop

{

number = arr[i]; // Number into array

{

if ((number %3 == 0) && (number %5 == 0)) // Checks if the number is divisible by 3 or 5

{

cout << "Number: " << number << " - FizzBuzz" << endl; // Output " - FizzBuzz" if divisible by 3 or 5

}

else if (number % 3 == 0) // Checks if the number is divisible by 3

{

cout << "Number: " << number << " - Fizz" << endl; // Output " - Fizz" if divisible by 3

}

else if (number % 5 == 0) // Checks if the number is divisible by 5

{

cout << "Number: " << number << " - Buzz" << endl; // Output " - Buzz" if divisible by 5

}

else

{

cout << number << " is NOT divisible by either 3 or 5." << endl; // Output if number not divisible by 5

cout << "Please enter another number: "; // Output asking for another number

cin >> number; // Input for new number

break;

}

}

}

return 0;

}