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I need to have the following homework answer: Show how the value ASCII "MIRIAM" is stored as hexadecimal in memory in Little Endian format starting...
I need to have the following homework answer:1. Show how the value ASCII “MIRIAM” is stored as hexadecimal in memory in Little Endian format starting at location 100 hexadecimal. Assume that each memory location stores two ASCII characters.Memory Location Value Stored1001011022. Perform the computations below given the two 8-bit binary words:1100 10101001 0110Compute Answer(A v B)’(A NOR B)(A ^ B)(A AND B)3. The content of AC in the basic computer is hexadecimal 79A0 and the initial value of E is 1. Determine the contents of AC, E, PC, AR, and IR in hexadecimal in each of the register –reference instructions from CLA to HLT. The initial value of PC is hexadecimal 156. Fill in the AC, PC, AR and IRIR-CLACLECMACMECIRCILINCSPASNASZASZEHLT4. An instruction at address 106 in the basic computer has I = 0, and an address part equal to 417 (all numbers are hexadecimal). The memory word at address 417 contains 16AB and the content of AC is 5E34. Go over the instruction cycle and determine the contents of registers PC, AR, DR, AC, and IR for each of the seven memory-reference instructions.IR-ANDADDLDASTABUNBSAISZ5. For X = 1110 0011 1001 0100, show the result of the following independent operations (i.e. each instruction occurs with X starting at the value above):________________________6. Write code that performs the computation:X = A + B + C * D +* E / Fusing CPUs that have the following instruction formats: Do not modify the values of A, B, C, D, E, or F. If necessary, use a temporary location T to store the intermediate results. a. three-operand instructions b. two-operand instructions c. one-operand instructions d. stack instructions7. Given the following set of events, show which routines the CPU is executing for times 0 to 100 ns. Each handler routine (with its interrupt request) takes 20 ns to complete. The priority of the interrupts ranges from IRQ6 as the highest priority interrupt to IRQ0 as the lowest priority interrupt.ActionStart of main programIRQ1IRQ3IRQ4IRQ6ActionStart of Main ProgramIRQ1
