I was told to rewrite the algorithm below to a standard algorithm. I am not sure if I need an exit statement or

I was told to rewrite the algorithm below to a standard algorithm. I am not sure if I need an exit statement or

not.

Here is my algorithm and the image down below is the algorithm that I needed to rewrite:

Function location (S, n, x, low, high)

// S is an integer type that represented the sorted (nondecreasing order) input array of n integers //

// n is an integer type that represented the input size of an array //

// x is an integer type that represented the input key value //

//low is an integer type that represented the minimum value in the array //

//high is an integer type represented the maximum value in the array //

Integer S (1 : n), n, x, low, high, mid, index

// index is an integer type represented the return value //

if (low > high) then

              index ← 0

else

              mid = (low + high) / 2

              if (x = S[mid]) then

                        index ← mid

              else

                       if (x < S[mid]) then

                               ndex ← location (low, mid - 1)

              else

                             index ← location (mid + 1, high)

              return (index)

              exit #### Do I need the exit here or just take it off? ####

end location

Algorithm 2.1Binary Search (Recursive)Problem: Determine whether x is in the sorted array S of size n.Inputs: positive integer n, sorted (nondecreasing order) array of keys S indexedfrom 1 to n, a key x.Outputs: location, the location of x in S (0 if x is not in S).index location (index low, index high)index mid;if ( low > high )return 0;else {mid = [( low + high )/2] ;if (x == S[mid])return midelse if (x < S[mid])return location (low, mid - 1);elsereturn location (mid + 1, high );