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I was wondering if anybody out there could help explain to me how to this problem is solved?

I was wondering if anybody out there could help explain to me how to this problem is solved?

starting point: (2,2)

starting tangent vector: R′(0)=0i+2j.......<0,2>

ending point: (7, 2e-1)

ending tangent vector: R′(1)=12i+(2e−2)j......<12, 2e-2>

1.2 With the same starting point, starting tangent vector, ending point, and ending tangent

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