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QUESTION

Nov 12, 2024

I1.if x=0,y=0,then 2x/y÷6y/x=? 2).if 2x-5=5x+4, then x²+x=? 3).Evaluate 16\(16⅔\)=4).if (3+x)²=9+ax+x²,for allx thenSo i want to teach you all about precalculus now my names are mr.Edwins . Now many p

I1.if x=0,y=0,then 2x/y÷6y/x=?

2).if 2x-5=5x+4, then x²+x=?

3).Evaluate 16\(16⅔\)=
4).if (3+x)²=9+ax+x²,for allx then

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ANSWER

Solution 1.
2x/y÷6y/x automatically the answer becames zero.
Solution 2
2x-5 is same as 5x+4 so here collect the like terms together and we will have 2x-5x=4+5 which will give us -3x=9=x,,then (-3)²+(-3)=9-3=6 so our answer is 6
Solution
16⅔ this is simple in that we will expand(3+x)² which is equivalent to 9+6x+x² and that is our answer.

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