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QUESTION

# If 0.5 mole of BaCl2 is mixed with 0.2 moles of Na3PO4 calculate the maximum no of Mole of Ba(PO4)2 that will be formed?

The maximum amount of "Ba"_3"(PO"_4")"_2" that can be produced is "0.1 mol".

"3BaCl"_2("aq")"+ 2Na"_3"PO"_4("aq")rarr"Ba"_3"(PO"_4)_2("s") + "6NaCl(aq)"
0.5"mol BaCl"_2xx(1"mol Ba"_3"(PO"_4")"_2)/(3"mol BaCl"_2)="0.2 mol Ba"_3"(PO"_4")"_2" (rounded to one significant figure)
0.2"mol Na"_3"PO"_4xx(1"mol Ba"_3"(PO"_4")"_2)/(2"mol Na"_3"PO"_4)="0.1 mol Ba"_3"(PO"_4")"_2"
"Na"_3"PO"_4" is the limiting reactant and the maximum amount of "Ba"_3"(PO"_4")"_2" that can be produced by this reaction is "0.1 mol".