If ##sin (x) = 0.5##, how do you find the value of x?

x=n##Pi##+##(-1)^nPi/6##............general solution x=##Pi/6## if x ##in## [0,2##Pi##]

x=n##Pi##+##(-1)^nalpha## is the general solution of, ##sinx=sin alpha## here ##alpha=Pi/6## and n=0,1,2,3,4.........so on (or n is the number of cycles)