If the total revenue function for a hammer is ##R=36x-.01x^2##, then sale of how many hammers, ##x##, will maximize the total revenue in dollars?

I got ##1800## hammers or ##$32400##

We can derive our function and set it equal to zero. This will give us a max or min (in this case I know it is a max) and the corresponding ##x## value: so ##R'=36-0.02x## set it equal to zero: ##36-0.02x=0## rearrange: ##x=36/0.02=1800## hammers