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In a random sample of 40 refrigerators, the mean repair cost was $149.00 and the population standard deviation is $15. Construct a 90 %confidence...
In a random sample of 40 refrigerators, the mean repair cost was $149.00 and the population standard deviation is $15.80. Construct a 90 %confidence interval for the population mean repair cost. Interpret the results.
Construct a 90%confidence interval for t he population mean repair cost. The 90%confidence interval is .( , ).(Round to two decimal places as needed.)Interpret you results. Choose the correct answer below.
A.With 90%confidence, it can be said that the confidence interval contains the true mean repair cost.
B.The confidence interval contains 90%of the mean repair costs.
C.With 90%confidence, it can be said that the confidence interval contains the sample mean repair cost.
