Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
QUESTION
In each step in the process below has 80% yield. CH4+4Cl2 ---CCl4+4HCl CCl4+2HF -- CCl2F2+2HCl the CCl4 formed in the first step is used as a...
In each step in the process below has 80% yield. CH4+4Cl2 --->CCl4+4HCl CCl4+2HF --> CCl2F2+2HCl the CCl4 formed in the first step is used as a reactant in the second step. If 9.00 mol of CH4reacts, what is the total amount of HCl produced? Assume that Cl2and HF are present in the excess. explain please
