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# integral of (sqrt(1-ln(x)^2))/(xlnx)) so I substitute ln(x) for u amp; I get (sqrt(1-u^2)/(u)) then I substituted u for sin because its (a^2-x^2)

integral of (sqrt(1-ln(x)^2))/(xlnx))

so I substitute ln(x) for u & I get (sqrt(1-u^2)/(u))

then I substituted u for sin because its (a^2-x^2) trig integral so I get (sqrt(1-sin^2)/(sin)) dx/cos

then the cosines cancel out & I'm left with 1/sin(x) dx. Is my solution correct and if it is, what should I do next?