Answered You can hire a professional tutor to get the answer.
Iodide is oxidized by hydrogen peroxide according to the following mechanism:
Iodide is oxidized by hydrogen peroxide according to the following mechanism:
H 2 O 2 + I^ - → H 2 O + OI^ - (slow)
H^+ + OI^ - → HOI (fast)
HOI + H^+ + I^ - → I 2 + H 2 O (fast)
(a) What i s the overall reaction?
(b) What is the molecularity of each step?
(c) Write the rate equation for the rate-determining step.
(d) What are the intermediates in this reaction? (If none, write "none.")