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QUESTION
Lead(II) chromate, PbCrO4, is a yellow paint pigment (called chrome yellow) prepared by a precipitation reaction . In a preparation, 45.6 g of lead(II) chromate is obtained as a precipitate. How many moles of PbCrO4?
0.141 mol
Convert grams to moles by dividing 45.6g using g/mol of ##PbCrO_4##
##45.6cancel("g PbCrO"""_4) xx "1 mole"/(323 cancel("g PbCrO"""_4)) = "0.141 moles"##
