Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.

# lim →0[cos−1(3 )−cot−1( ) 3 −1] lim →0+ ( 2 −4 ) limx→0+ (e2x−4x)πx

lim →0[cos−1(3 )−cot−1( ) 3 −1]

lim →0+ ( 2 −4 ) limx→0+ (e2x−4x)πx