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Math 136/ Statistics 136 Please answer to all the questions carefully, and make your work legible. You may use Excel, Stat Crunch or different kind...
Math 136/ Statistics 136
Please answer to all the questions carefully, and make your work legible. You
may use Excel, Stat Crunch or different kind of software's to calculate and
graph the datas. You must turn in the project on the day of the Final, No Late
project is accepted. You may do the project in a group of two or individually.
1) Interview 20 women and 30 men between 18 to 60 years old, ask them
their ages and the number of hours that they work. These information
would be your populations. For each group find the followings:
(Please chose any 20 random number for this questions) if you need help for the number pls email me or ask through coursehero.
a)
Find the Mean, Median, and Mode, Standard deviation, Variance, the
percentile of 40, the z-score for the value of 35, Q1 and Q3 for the ages only.
b)
Construct a frequency distribution for men and women separately with 6
classes and use the lowest number as the lower class limit of the first
class. Then draw a histogram, for that frequency distribution for the
ages only.
c)
Draw boxplot and 5 number summary. Do you have outliers?
d)
Draw the bell shaped distribution.( Impirical Rule)
e) Create a sample of 10 men and 10 women from each group, find their
sample mean for the number of work hours. (Independent samples) Then
test the hypothesis that the average work hours for the men and the
women in the group is different. (∝=0.1) Sec 11.3
f) Use the datas from the samples that you created in part (e), and calculate the Coefficient of determination and find the least square regression line, then graph the line. [ You should consider the ages of people as x value (Horizontal-Axis) and the number of hours that they work as y value (Vertical-Axis).] Please explain that what kind of correlation exist between the ages of the people and the number of hours they work.
let me know if you have any question about the problem or not.