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Math
In the expansion of (x^2+a/x)^8, a is not equals to 0, the coefficient of x^7 is four times the coefficient of x^10. Find the value of a.
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********* using binomial ** *** ***** ** in *** bracketthe *** ****** **** *********** 8C3a^3 *** **** ****** **** coefficient 8C2a^28C3= *********** * ** *** *** * *********** = 28therefore ***** * * * *********************************** ********* and ******** ***** since a is not *** **************** a * * = * * a consder ******* ** *** as (a/x * x^2)^8Expanding ***** binomial ************ x^7 occurs with *********** ****** *** ********** **** *********** 8C6a^28C5= ** *** ****** * ** *** ********* (8-6)!=28So ***** = ********************** ******* *** ****** ************* ****** ***** ***** * not ***** ** ********** **************** * * ****** a = 2 ******