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QUESTION

Midsegment Theorem

I don't know how to do the triangle midsegment theorem and i need an easy way for it to be explained with examples

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Robert
Robert
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ANSWER

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*** **** joining *** ********* ** two opposite sides ** *** triangle ** ******** ** *** third **** *** half *** *******

** ** * ** ******

So ** **** is **** a segment ********* ******** **

= ** **** **

* parellogram so angle ****** So ** *

** * * +x = 360 ***** * *

***** **** 2x=266 ****** *****

CHF

*

** ** ******** ** alternating angles ** ************ **** angle **** The angle *****

***** *** ** *** same ** ***** *** * **

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ANSWER

Tutor has posted answer for $10.00. See answer's preview

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** *** triangle midsegment theorem if * **** ******* *** *** ***** ** a ******** ** *** **** ***** **** the **** must ** parallal ** *** third **** **

this ******** ** *** ** **** ** * FD CH = ** *** DG * ** * ***** ** *** ******* * *** CF/FD

= CH/HE = ***** * * *** the ****

** * | ** * as *** ********** ******* ********* ***** * *** *** ********* Δ CFH ***** ** *** *** ******* *** ** / **

* ** * ** * *** * *** ***** ** corresponding sides ** * similar ********* are ***** * CH * HE ** *

** * HE * ** + ** * ***** CH * ** ) *** ** * * ** ***

***** * 1/2 Now ** * DE * 1/2 (

from ***** ** So *** ** * *** *** **

= 55 * * = ** *** DE * ** ** * *** **

** * ** = **

* ** = ** * DG ( *** DG * ** ****** ** *** DE * * DG *** ** = **** ∴

** * *** X ** = **** = ** ***

pl ******** Δ *** * ** *** m *** FDG =

* *** *** *** DC * ***** = ***

* *** ** * ** * FC *

** * ** ( *** DF = ** ****** ** *** ** * 2DF *** DF * ***** * **** Similarly ***** = *** *

∵ DE = ** + ** = ** * DG

* *** DG * ** ****** ) *** DE * *** ** ** the ** DFG ***** Δ *** *** similar ** *** *** iem ∠ ***

= * *** *** are ***** and ************* sides enclosing *** ****** in **** *** ********* ** ***** = ***** * *** *** ************ This ** ** per *** * **** ***** **** ) ******* ** ********** *** ** * * ** * corresponding ***** of ******* Triangles are paralall ** * ∠

*** = * *** *** ****** * ***** - ∠ FHC * 180° - **** * ***** **** ** | * **

*** m∠ *** * * *** *** **** being ********* interior ****** ** ** had ****** ***** Δ *** * Δ DCE * *** FG / CE = ***** =

*** ******* ******* ⇒ ** * *** * ** * 1/2 X *** * *** m∠ *** * m∠ ***

= **** (∵ ** | * ** *** **** *** * m

*** *** **** being ********* interior ****** ) m∠ *** * **** *** = ∠ *** * 47 ** ( *** *** * Δ ***

*** ************* ****** *** *** ***** ∠ *** *** equal ** ( *** ** * | ** ***** ** is *** *********** ∴ ****** *** *** * ∠

*** **** being ********* ******** angles **** I **** ********* to *** *** *** ************ ** ******** at *** ********* Thanks *** the *************

****** **** free ** message ** ** **** ** *** *****

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